View source for Integer byte encoding peculiarity

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According to Matt Howard 20210816, there is a "peculiarity with how integers are encoded in bytes.  

It's signed integers.  

If you just return <code>run '(q . 0xd7)'</code> you get -41 because the most significant bit is set and that's telling the interpreter to read this as a negative number.  

If you add some leading zeroes <code>run '(q . 0x00d7)'</code>, it should pop out as you would expect". 

Returns 215.

<h1>Original concern</h1>

Q: I still have one question: why does <code>brun '(- (q . 0xd7) (q . 0x1))'</code> return -42?

A: <code>hex(-42 & 0xff) == '0xd6''</code> I see thanks!